2x^2+74x-798=0

Solution for 2x^2+74x-798=0 equation:

2x^2+74x-798=0

a = 2; b = 74; c = -798;
Δ = b2-4ac
Δ = 742-4·2·(-798)
Δ = 11860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11860}=\sqrt{4*2965}=\sqrt{4}*\sqrt{2965}=2\sqrt{2965}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-2\sqrt{2965}}{2*2}=\frac{-74-2\sqrt{2965}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+2\sqrt{2965}}{2*2}=\frac{-74+2\sqrt{2965}}{4}
$